Shaneya purchased a membership to play basketball at her local gym. The membership costs $75 for the year, plus she pays $3 to rent equipment each time she goes. If Shaneya doesn't want to spend any more than $150 on basketball for the year, what is the maximum amount of times can she go to the gym to play?

25

Step-by-step explanation:

Step one:

given data

We are told that Shaneya purchased a membership to play basketball at her local gym.

Costs =  $75 for the year,

Rent =  $3 for equipment each time she goes

Given that she has $150 to spend,

Step two:

Firstly, let us model the situation

let the total amount she has to spend be y

and the number of time she goes to the gym be x

y= 75+3x

for y= 150, let us find the value of x

150= 75+3x

150-75= 3x

75= 3x

divide both sides by 3

x= 75/3

x=25 times

The maximum amount of times is 25

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.