Three consecutive integers are listed in increasing order. If their sum is 102, what is the second integer in the list?

Second integer = 34

Step-by-step explanation:

Given:

Sum of 3 consecutive integers = 102

Find:

Second integer

Computation:

Assume;

First integer = x

So,

Second integer = (x+1)

Third integer = (x+2)

So,

x + x + 1 + x + 2 = 102

3x + 3 = 102

x = 33

Second integer = (x+1)

Second integer = (33+1)

Second integer = 34

answer: 1,380

step-by-step explanation:

1: you turn %15 into a decimal by moving the decimal point two places to the left.

2: and then you multiply .15 by 1,200 , which will get you 180.00

3: from there you will add 180 to 1,200

4: which will get you 1,380

hope it *im kind of slow so idk if my answer is right*