Use I'Hopital's Rule more than once to rewrite the limit in its final form as lim x --> 0 lim x --> 0 e^x -sinx - 1/ x^4 + 7x^3 + 8x^2

To compute the limit

notice that when x = 0, both the numerator and denominator converge to 0. Apply l'Hopital's rule once gives

but again, this returns the indeterminate form 0/0. Applying again gives

so that the numerator converges to e⁰ + sin(0) = 1, and the denominator converges to 12•0² + 42•0 + 16 = 16.

So the limit is 1/16.

y = - 6

step-by-step explanation:

given the point (- 2, y) lies on the graph then it is a solution of it's equation.

substitute x = - 2 into the equation for value of y

y = 3(- 2) = 3 × - 2 = - 6

the point on the graph is (- 2, 6)

connie < felicia < stew

step-by-step explanation:

stew:

we need to find the slope

m = (y2-y1)/ (x2-x1)

    = (2650-795)/(10-3)

    = 1855/7

265 words per minute

connie:

we need to find the slope

m = (y2-y1)/ (x2-x1)

we have two points (0,0) and (4,800)

m = (800-0)/(4-0)

  m = 800/4

    200 words per minute

felicia:

260 words per minute

200< 260 < 265

connie < felicia < stew