A recent report indicated that 22 percent of the households in a certain community speak a language other than English at home. A reporter will randomly select a household from the
community until the first houehold that speaks a language other than English at home is
selected. Let random variable Q represent the number of attempts needed until the first
household that speaks a language other than English at home is selected. The random variable
Q has a geometric distribution with p = 0.22. Which of the following is closest to the variance
of the random variable?

10 - 8 = -2

  8 - 6 = -2

etc, so -2 is the common difference

step-by-step explanation:

asnwer is (g o h o f)(x) = 2x - 6/x + 7

step-by-step explanation:

given,

f(x) = x - 3/x

g(x) = x + 3

h(x) = 2x + 1

we need to find : (g o h o f)(x)

we can write (g o h o f)(x) = g[ h{ f(x) } ]

so first we find h{f(x)}

h{f(x)} = f(x) + 3 = (x - 3/x) + 3

h{f(x)} = x - 3/x + 3

now we find g[ h{ f(x) } ].

g[ h{ f(x) } ] = g(x - 3/x + 3)       {plug h{f(x)} = x - 3/x + 3 in g[h{f(x)}] }

g(x - 3/x + 3) = 2 (x - 3/x + 3) + 1

                    = 2x - 6/x + 6 + 1

                    = 2x - 6/x + 7

hence we get (g o h o f)(x) = 2x - 6/x + 7

the answer is b to that question