If θ is in standard position and -180° < θ <-90°, then θ terminates in Quadrant . 1) II
2) III
3) I
4) IV

Should be quadrant 3

Step-by-step explanation:

1 is everything in -360

2 is everything in -270

3 is everything in -180

4 is everything in -90

So basically it is less than -90 so it couldn’t be in quadrant 4 it would be before it so quadrant 3. Sorry if this is incorrect but it is to the best of my knowledge

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2

10

step-by-step explanation: