What is the equation of the line that passes through the point (-3, 1) and
has a slope of 4/3?

Step-by-step explanation:

use point-slope formula   y-y1 = m(x-x1) with your given point (x1,y1)=(-3,1) and slope m of 4/3

y-1 =4/3(x-(-3))

y-1 = 4/3(x+3)

y-1 =4/3x +4

y = 4/3x + 4 +1

y = 4/3x +5

:)