Consider the numbers z= sqr2 (cos 45º + i sin 45° )and w = 2(cos 90° + i sin 90). Fill in the blanks to complete the statements.

In rectangular form, z - w = 1 - i

In polar form z-w=

= sqr2 (cos + i sin )

RECTANGULAR FORM: z -w = 1- 1i

POLAR FORM: z-w = √2(cos135°+i sin135°)

Step-by-step explanation:

Find the image attached

Given the following complex numbers

z = √2 (cos 45º + i sin 45° )

w = 2(cos 90° + i sin 90).

The complex number in rectangular form is expressed as z = x+iy

(x, y) are the rectangular coordinates

Given

z = √2 (cos 45º + i sin 45° )

z = √2 (1/√2+ ( 1/√2)i )

z =  √2(1/√2) +  √2(1/√2)i

z = 1 + i .... 1

Also;

w = 2(cos 90° + i sin 90)

w = 2(0 + 1i)

w  = 2(0) + 2i

w = 0+2i ....2

Take their difference:

z - w = 1 + i - (0+2i)

z-w = 1+i-0-2i

z-w = 1-0+i-2i

z-w = 1-i

Hence the values that goes into the box is 1.

z-w = 1 - 1i

In Polar form;

Get the modulus of the resulting complex number:

|z-w| = √1²+1²

|z-w| = √2

Get the argument:

Since tan is negative in the second quadrant, the angle will be 180-45 = 135°

The polar form of the complex umber is expressed as;

z-w = |z-w|(cosθ-isinθ)

z-w = √2(cos135°+i sin135°)

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.

they can both be solutions depends on the equation

step-by-step explanation:

what is the equation? ?