A department store's survey suggests that 76% of shoppers buy food, 49% buy clothes, and 28% buy both food and clothes Suppose a shopper is selected from the store at random and learn that they buy clothes. What is the
probability that the shopper also buys food?
027
0.39
0.57
0.64

0.57

Step-by-step explanation:

Given that:

food = f ; c = clothes

P(f) = 0.76

P(C) = 0.49

P(fnC) = 0.28

Suppose a shopper is selected from the store at random and learn that they buy clothes. What is the probability that the shopper also buys food?

P(f Given C) = P(f | C)

P(f | c) = p(fnC) / p(C)

P(f | c) = 0.28 / 0.49

P(f | c) = 0.5714

P(f | c) = 0.57

10/60

step-by-step explanation:

if you divide 10 by 60 the answer is 0.166666 while if you divide or solve the other problems it equals 0.6