At time t ≥ 0, the velocity of a body moving along the s-axis is v = t² -5t +4. When is the body moving backwards Check comments for multiple choice answers

A

Step-by-step explanation:

The velocity of a moving body is given by the equation:

Is the velocity is positive (v>0), then our object will be moving forwards.

And if the velocity is negative (v<0), then our object will be moving backwards.

We want to find between which interval(s) is the object moving backwards. Hence, the second condition. Therefore:

By substitution:

Solve. To do so, we can first solve for t and then test values. By factoring:

Zero Product Property:

Now, by testing values for t<1, 1<t<4, and t>4, we see that:

So, the (only) interval for which v is <0 is the second interval: 1<t<4.

Hence, our answer is A.

66.666666667%

step-by-step explanation:

divide 150 by 100

divide 100 by 1.5

there you go!

decreased by 33.333333334%