F(x)=3x+3, then f^-1(x)=

f^ - 1 (x) = x/3 + 1/3 is not the inverse function of f(x) = 3x + 1

Step-by-step explanation:

F(x) = 3x + 1

Inverse:

x = 3y + 1

3y = x - 1

y = x/3 - 1/3 or f^ - 1 (x) = x/3 - 1/3

so

f^ - 1 (x) = x/3 + 1/3 is not the inverse function of f(x) = 3x + 1

what are you trying to solve here

step-by-step explanation:

both graphs increase on their domain

neither graph has a y-intercept

step-by-step explanation:

the following points can be visualized easily from the graph