Part B Enter the numerical coordinates of the vertices of quadrilateral ABCD in the table. (Point A has been done for you.) Then predict the numerical
coordinates of the vertices of quadrilateral A'B'C'D' as the figure translates four different ways: 7 units up, 1 unit down, 4 units to the right, and 3
units to the left.

9514 1404 393

  up: (-3, 5); down: (-3, -3); right: (1, -2); left: (-6, -2)

Step-by-step explanation:

As you know, the coordinates of a given point tell you the distance ...

  (right, up)

So, a displacement 7 units up adds 7 to the second coordinate value:

  A(-3, -2) ⇒ A'(-3, -2+7) = A'(-3, 5) . . . . 7 units up

Likewise, 1 unit down subtracts 1 unit from the second coordinate value:

  A(-3, -2) ⇒ A'(-3, -3) . . . . 1 unit down

__

Similarly, left-right changes affect only the first coordinate. Displacements right are added; displacements left are subtracted.

  A(-3, -2) ⇒ A'(-3+4, -2) = A'(1, -2) . . . . 4 units right

  A(-3, -2) ⇒ A'(-6, -2) . . . . 3 units left

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c