In an interval whose length is z seconds, a body moves (32z + 2z^ 2 ) ft. What is the average speed v of the body in this interval?

This question is incomplete, the complete question is;

In an interval whose length is z seconds, a body moves (32z + 2z²) ft.

What is the average speed v of the body in this interval?

the average speed v of the body in this interval is 32 + 2z ft/s

Step-by-step explanation:

Given that;

Length of travel = z seconds

also the body moves (32z + 2z²) ft

i.e

distance travelled = (32z + 2z²) ft

average speed v of the body in this interval = ?

Now to get the Average Speed

we simply say;

Average Speed V =  (32z + 2z²) / z

Average Speed V = 32 + 2z ft/s

Therefore the average speed v of the body in this interval is 32 + 2z ft/s

step-by-step explanation:

there are 36 inches in a yard

25 : 36 = 0.69 yards (you can round to 0.70)