Mathematics, 04.01.2021 07:10 cork6

Drag each tile to the correct location on the algebraic problem. Not all tiles will be used, Fill in the missing steps and justifications used to solve the given equation.
Subtraction property of equality
61 - 7 - 12 = 12 + 7
Simplification
61 - 7 + 7 = 12 +7
Addition property of equality
Multiplication property of equality
1 = 114 = =
41-7 = -20 +12
1. Given
43 - 7 + 20 = -21 + 12 + 23
2. Addition property of equality
6.3 - 7 = 12
3.
4.
63 = 19
5. Simplification
6. Division property of equality
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Drag each tile to the correct location on the algebraic problem. Not all tiles will be used,

Fill

Answers: 1

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Answers

Answer from: diane8879

The correct justification, provides the right reasons for the given

mathematical operation.

Responses:

3. Simplification

6·x - 7 + 7 = 12 + 7 4. Addition property of equality

How are the correct justifications found?

The two column solution is presented as follows;

Step Justification

4·x - 7 = -2·x + 12 1. Gives

4·x - 7 + 2·x = -2·x + 12 + 2·x 2. Addition property of equality

6·x - 7 = 12 3. Simplification

6·x - 7 + 7 = 12 + 7 4. Addition property of equality

6·x = 19 5. Simplification

$\dfrac{6 \cdot x}{6} = \dfrac{19}{6}$ 6. Division property of equality

Learn more about the properties of equality here:

link

Answer from: anniebear

Answer/Step-by-step explanation:

4x - 7 = -2x + 12 (Given)

Add 2x to both sides

4x - 7 + 2x = -2x + 12 + 2x (Addition property of equality)

6x - 7 = 12 (Simplication)

Add 7 to both sides

6x - 7 + 7 = 12 + 7 (Addition property of equality)

6x = 19 (Simplification)

Divide both sides by 6

$\frac{6x}{6} = \frac{19}{6}$ (Division property of equality)

$x = \frac{19}{6}$

Answer from: Quest

the answer will be the last one

Which equation represents a line that passes through (4,3/4) and has a slope of 3/4

Answer from: Quest

x= -3 and $x=\frac{-3+/-3i\sqrt{3} }{2}$

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

$(x^3-a^3)=$ $(x-a)(x^2+ax+a^2)$

where a is the cube root of $a^3$ .

here this is 27 and the cube root of 27 is 3. so we write using the form:

$(x-3)(x^2+(3)x+3^2)\\(x-3)(x^2+3x+9)$ .

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

$x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}$

where a = 1, b=3, and c=9

$x=\frac{-3+/-\sqrt{3^2-4(1)(9)} }{2(1)} \\x=\frac{-3+/-\sqrt{9-36)} }{2} \\x=\frac{-3+/-\sqrt{-27)} }{2}\\x=\frac{-3+/-3i\sqrt{3} }{2}$

this cubic has two complex roots.

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