A lent B rs 32500 to purchase a car at 12.5% p. A

6,483.75

Step-by-step explanation:

Calculation to find the interest paid by B after 3/2 year

First step is to calculate the Compound interest amountUsing this formula

Interest paid= P(1 + r/100)^Time

Where,

P represent principal=32,500

r represent Rate of interest = 12.5%/2 = 6.25%

T represent Time=3/2 years

Let plug in the formula

Compound interest amount= 32,500(1 + 6.25/100)^2*3/2

Compound interest amount= 32,500([1+.0625)^3

Compound interest amount= 32,500(1.0625)^3

Compound interest amount= 32,500 *1.1995

Compound interest amount= 38,983.75

Now let calculate the Interest paid by B

Interest paid by B = 38,983.75 - 32,500

Interest paid by B = 6,483.75

Therefore the interest paid by B after 3/2 year will be 6,483.75

in simplified version   it would be x ≤-4

step-by-step explanation:

multiply each term in x ≤-4 by -1

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3