If you apply the changes below to the quadratic parent function, f(x) = x2, what is the equation of the new function?
• Shift 1 unit right
• Vertically stretch by a factor of 5.
• Reflect over the x-axis.
A. g(x) = -5(x - 1)2
B. g(x) = 5x2 - 1
C. g(x) = (-5x + 1)2
D. g(x) = -5(x + 1)2

he has now walked a total of what?

if i know what this is maybe i can

step-by-step explanation:

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true

ok thats very interesting