HELP QUICK Write the equation of a line that is parallel to the graph of 3y = 2x − 3 and passes through the point
(−3, 4).

y = 2/3x + 6

Step-by-step explanation:

First, put the original equation in y = mx + b form

3y = 2x − 3

y = 2/3x - 1

The slope of the other line will also be 2/3, since parallel lines have the same slope.

Plug in this slope and the given point into y = mx + b, and solve for b:

y = mx + b

4 = 2/3(-3) + b

4 = -2 + b

6 = b

Plug in the slope and b:

y = 2/3x + 6 is the equation of the line

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step-by-step explanation: