PLZ HELP Write an equation of the given line in slope-intercept form with the given points (1,1) and (4,2)

Find the equation of a line with a given slope and containing the given point. Write the equation in slope-intercept form.

m = − 3/4, point (8, −4)

Find the equation of a line with a given slope and containing the given point. Write the equation in slope-intercept form.

m = − 7/2, point (−8, −4)

Find the equation of a line with a given slope and containing the given point. Write the equation in slope-intercept form.

m = −6, point (−1, −4)

Find the equation of a line with a given slope and containing the given point. Write the equation in slope-intercept form.

a horizontal line containing (−3, -5). #2

avatar+51

+2

I'm going to answer the solution in Point-Slope and Slope-Intercept.

Slope - Intercept form is this: y = mx + b

We know that (x, y) is a point on the line, m is the slope, and b is the y-intercept.

From the given information we have that it has a slope of 2 (m = 2), and one of the points on the line is (3, 9) which means that (x = 3, y = 9)

Plugging in we get:

y = mx + b

9 = 2*3 + b

9 = 6 + b

b = 3

Therefore the y-intercept is 3. After having this information we can construct our equation.

We now have to put this in the point-slope form which is: (y - y1) = m(x - x1)

Transferring what we had before we can plugin and get y - 9 = 2(x - 3)

Comment down if you have any queries or any questions on the solution. Tell me as soon as possible. Good luck in your Algebra Pursuit!! :)

Enjoy :)

So our answer is:

y - 9 = 2(x - 3).

constants mean the stopped points or the points on a graph that nothing is changing, hope this

step-by-step explanation: