Let f and g be functions such that Limit of f (x) as x approaches c = Limit of g (x) = k as x approaches c = k.. If k ≠ 0, then Limit of StartFraction f (x) Over g (x) EndFraction as x approaches a = 0.
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k.
k2.

The answer to #44 is 10.4444, so g is the answer i divided the time by the miles. 47

38+105= 143, 39+104=143, and you will find then adding the numbers on opposite sides, moving inwards yields the answer 138 every time. because of this, you’re going to multiply 138 times the number of pairs, which is 34. therefore, 34*138= 4692(i’m sorry if it’s the wrong numbers, but it’s the right concept)