An object of mass 20kg is dropped from a height . Find the potential and kinetic energy if the heights are 4,3,2,1, just above the ground. (Take value of g as 10 m/s-2

At 4 meters, the potential energy is 800 Joules

At 3 meters, the potential energy is 600 Joules

At 2 meters, the potential energy is 400 Joules

At 1 meter, the potential energy is 200 Joules

Step-by-step explanation:

The given mass of the object = 20 kg

The Potential Energy of an object at a height is. P.E. = m × g × h

Where;

m = The mass of the object

g = The acceleration due to gravity taken as 10 m/s²

h = The height of the object

The potential energy if the height is 4 meters is given as follows;

P.E. = 20 kg × 10 m/s² × 4 m = 800 Joules

The potential energy if the height is 3 meters is given as follows;

P.E. = 20 kg × 10 m/s² × 3 m = 600 Joules

The potential energy if the height is 2 meters is given as follows;

P.E. = 20 kg × 10 m/s² × 2 m = 400 Joules

The potential energy if the height is 1 meter is given as follows;

P.E. = 20 kg × 10 m/s² × 1 m = 200 Joules.

#15. square

step-by-step explanation:

because quadrilatural (idk how to spell it) means somthing that is not 3d or like, equal sides (or somthing like that   you know what i meanz)

hope this halps!

bai!

what is the question?

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