The average score of a sample of 87 senior business majors at UTC who took the Graduate Management Admission Test was 510 with a standard deviation of sample 36. Provide a 98% confidence interval for the mean of the population.

500.85 to 519.15

Step-by-step explanation:

The computation is shown below;

The z value for the 98% confidence interval is 2.33

Now the margin of error is

= (z × standard deviation) ÷ √n

= (2.33 × 36) ÷ √87

= (83.88 ) ÷ √87

= 83.88 ÷ 9.327379

= 8.99

= 9

Now The confidence interval mean is

= (510 - 9) (510 +9)

= (501) ; (519)

1; 35 is the ratio

step-by-step explanation:

step-by-step explanation:

ok one would be money, and the other would be refreshments or something similar. if each bag of popcorn is 5.00 and each drink is half of that that means drinks are 2.50 the proper way to do that would to look and see how much of each you can buy without exceeding a limit of 30.00