An amusement park reduced the admission price to $15.50 per day, but now charges $1.50 per ride. Mark has $26 to spend on admission and rides. Write an algebraic equation to find how many rides Mark can ride in one day.

15.50 + 1.50x ≤ 26

Step-by-step explanation:

Given that:

Total amount to spend = $26

Admission fee = $15.50

Charge per ride = $1.50

Number of rides Mike can take in a day:

Let number of rides can take In a day = x

[Admission fee + (charge per ride * number of rides)] less than equal to total amount

15.50 + 1.50x ≤ total amount

15.50 + 1.50x ≤ 26

1.50x ≤ 26 - 15.50

1.50x ≤ 10.50

Divide both sides by 1.50

x ≤ 10.50 / 1.50

x ≤ 7

Hence, number of rides per day = 7

8

step-by-step explanation:

to find the amount of gift bags to use all the supplies, find the gcf or greatest common factor. this is the largest number which multiplies evenly into each term.

48 has factors: 1, 2, 3, 4, 6, 8, 12. 16, 24, 48

80 has factors: 1, 2, 4, 5, 8, 10, 16, 20, 40, 80

64 has factors: 1, 2, 4, 8, 8, 16, 32, 64

the highest number factor they all share in common is 8. this means there will be 8 bags with 6 pencils, 10 markers, and 8 stickers in each bag.

aloha~! my name is zalgo and i am here to you out on this amazing day. to answer your question, yes, nonzero numbers can have a greatest common factor and that would be 1. still don't get it? let me considering every number is divisible by 1 and hence every number has 1 as a factor of theirs. so, if 2 nonzero numbers didn't share any gcf (greatest common factor), they would still have a factor in common and that would be 1.

i hope that this ! : p

"stay and stay proud! " - zalgo

(by the way, do you mind marking me as brainliest? i'd greatly appreciate it! mahalo! x3)