GIVING OUT FOR WHOEVER IS CORRECT AND FAST! The length of a rectangle is twice as long as it's width. The perimeter of this rectangle is how many times longer than the shorter side?

The formula for perimeter is the sum of
twice the width and twice the length, so
the formula would be:
Perimeter = 2W + 2L

In this problem:
Width is unknown (x)
Length is twice the width (2x)
and Perimeter = 60, so to set it up:
60 = 2x + 2(2x)
60 = 2x + 4x
60 = 6x
x = 10
Width = 10; Length = 20