A line passes through the point (-2, 4), and its y-intercept is (0,6). What is the equation of the line that is perpendicular to the first line and passes through the point (5, 4)?

y = -x + 9

Step-by-step explanation:

The line that passes through the points (-2,4) and (0,6) has a slope of 1, and a y intercept of 6. The equation to the first line is y = x + 6. and perpendicular lines always have the opposite, reciprocal slope of the other line. So the slope for the second line would be -1. A line with the slope of -1 and a point of (5,4) would contain the points (5,4) , (4,5) , (3,6) , (2,7) , (1,8) , and (0,9) , which is the y intercept for the second line. So the equation for the second line would be y = -x + 9

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752