5. Consider the ellipse (x^(2))/(16)+(y^(2))/(100)=1 .The tangent to this ellipse at (m, n) has x -intercept A=(a,0) and y- intercept B=(0,b) where a and b are positive. (a) Show that ab=(1600)/(mn) . (b) Use the relationship in part(a) and the fact that (m, n) lies on the ellipse to find the minimum value of ab .

a=r

d=q

c=p

b=s

hope this !

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x

the answer is 99.