Grab the image of parallelogram PQRS after a reflection across the line y = -3.

See the diagram below

The locations of the reflected points are:

============================================================

Explanation:

To get the diagram shown below, we'll reflect each point one at a time.

First note that y = -3 is a horizontal line through -3 on the y axis. Every point on this line has y coordinate of -3. Eg: (0,-3) and (1,-3) are on this line.

Then we count the vertical distance from P to this horizontal line. You should count out 3 units. We must move 3 units down to go from P to the horizontal line, and then we move another 3 units down to arrive at the location of P' = (0,-6)

Point Q will move 6 units to arrive at the horizontal line and then move another 6 units to arrive at (0, -9). This is the location of point Q'.

Points R and S will follow the same idea, although they will move a different amount because they aren't the same distance away compared to P or Q. You'll have to count the number of spaces from the point you're reflecting to the line of reflection, then count that number of spaces to go beyond the line of reflection.

As you can probably guess by now, points P and P' are the same distance away from the line of reflection (which is something to be expected due to reflections preserving distances). Similarly Q and Q' are the same distance away from the line of reflection, and so on.

------------------

As an alternative method, you can follow these steps

As an example: P(0,0) shifts 3 units up to (0,3). Then that reflects over the x axis to (0,-3). Then we shift 3 units down to arrive at P ' (0, -6). Points Q,R,S follow these same steps.

they can both be solutions depends on the equation

step-by-step explanation:

what is the equation? ?

step-by-step explanation:

4  

25

5258y

54.

t5

5r

54

5856

542

5458

86

.8558.65

565

565

55898

786

8/95

5896

8656265

556478