49.00 A curious student has a bag of multi-colored candies. He wants to know how many of each color are in the bag. He
makes the following observations
Red
Green
Yellow
Purple
Blue
14
36
7
19
3
After he counts all the colors, he eats four green candies, and puts the rest in the bag. What is the probability that
next time, he will choose a red candy?
a 0.14
c. 0.18
b. 0.17
d. 0.19
Please select the best answer from the choices provided
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D, 0.19

Step-by-step explanation:

So first you add up all the candies

you’ll get 79 pieces of candy

So 4 pieces of green candy

So we can just subtract 4 from 79 you’ll get 75 pieces

It still works becuase we know that 4 pieces gone are green so the other candies still have the same amount

Now there are 14 red pieces

So 14/75

Now simplify that and you’ll Get

0.18666666

Now round that, 0.19

answer: (1,3) and (-2,0) i think.

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form