Complete the function digits(n) that returns how many digits the number has. For example: 25 has 2 digits and 144 has 3 digits

Step-by-step explanation:

We can get this done by using the code

def digits(n):

count = 0

if n == 0:

return 1

while (n > 0):

count += 1

n= n//10

return count

Also, another way of putting it is by saying

def digits(n):

return len(str(n))

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print(digits(25)) # Should print 2

print(digits(144)) # Should print 3

print(digits(1000)) # Should print 4

print(digits(0)) # Should print 1

Doing this way, we've told the system to count the number of figures that exist in the number. If it's 1000 to 9999, then it records it as 4 digits. If it's 100 - 999, then it records it as 3 digits. If it's 10 - 99, it records as 2 digits. If it's 0 - 9, then it has to record it as a single digit.

Thanks

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

the answer is b.

step-by-step explanation:

identity property is where 0+whatever number=whatever number. basically 0+ a number.