Find the coordinates of a point in Quadrant 3 that makes the following triangles congruent. Triangle GHJ: G (1,-6), H (2,-5), J (2,1)

Triangle NOP: N (-6,1), O (-5,2)

A. P(-3,-4)

B. P(-4,-3)

C. P(-5,-6)

D. (-6,-5)

y > 1/3x

y < = -x + 4

hope this : )

ou would have 12 of each

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl