Recognizing the No-Solution Case Algebraically Consider the system of equations:
x2 + y2 = 8
x=3
Solving for one variable:
Work is shown to solve for the system of equations.
Why does the answer for y indicate that the system has
no real-number solutions?
1. Substitute:
(3)2 + y2 = 8
* The solution does not solve for x first.
O The values for y are square roots of negative
numbers.
The values for y have a positive and a negative
value.
O The values for y have square roots.
2. Simplify:
9 + y2 = 8
3. Isolate:
y²=-1
4. Solve fory:
y = -1
No solution

black/brown

step-by-step explanation:

well, you see here, jamal was born to 2 parents, his mother who he lives with and his father who left at a young age and who happens to be younger than him. he stole cookies because he has to steal food due to the fact that he spends his government poverty checks on pot and women.

98 points djdjsi zisksis sjsjsi sisksj sksjdj sksks sjsisj

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube