In the given figures find x and y

1) x = 40° & y = 50°

2) x = 100° & y = 80°

Step-by-step explanation:

1)

ABCD is a cyclic quadrilateral (∵ all the vertices of the quadrilateral are touching on the circle). As it is a cyclic quadrilateral , sum of it's opposite angles will be 180°.

⇒ ∠ADC + ∠ABC = 180°

⇒ 130° + y = 180°

⇒ y = 180 - 130 = 50°

In ΔABC ,

∠ACB = 90° (∵ AB is the diameter of the circle and a diameter subtends an angle of 90° on any point on circle.)

Using angle sum property of triangle ,

∠ABC + ∠ACB + ∠CAB = 180°

⇒ y + 90° + x = 180°

⇒ x + 50° + 90° = 180°

⇒ x + 140° = 180°

⇒ x = 180 - 140 = 40°

2)

ΔABC is an isosceles triangle (∵AB = AC). As it is an isosceles triangle , it's base angles will be equal. So , ∠ABC = ∠ACB = 50°

Using angle sum property of triangle ,

∠ABC + ∠ACB + ∠BAC = 180°

⇒ 50° + 50° + y = 180°

⇒ y + 100° = 180°

⇒ y = 180 - 100 = 80°

ABEC is a cyclic quadrilateral (∵ all the vertices of the quadrilateral are on the circle.). As it is a cyclic quadrilateral , sum of it's opposite angles will be 180°.

⇒ ∠BAC + ∠BEC = 180°

⇒ y + x = 180°

⇒ x + 80° = 180°

⇒ x = 180 - 80 = 100°

40 i don’t know lololol

3

step-by-step explanation: