Plsss help asappp :,)

2. x² + 8y²

3. -6 - 2y³ + 10y²

4. 3a² - 2a

Step-by-step explanation:

2. Two minuses make a plus.

(10x² + 4y²) - (9x² - 4y²) = 10x² + 4y² - 9x² + 4y²

Evaluate like terms.

10x² + 4y² - 9x² + 4y² = x² + 8y²

3. When multiplying terms in a bracket, you must multiply the term outside the bracket to all the terms in the bracket.

-2y²(3y² + y - 5) = (-2y² × 3y²) + (-2y² × y) + (-2y² × -5)

                          = (-6) + (-2y³) + (10y²)

                          = -6 - 2y³ + 10y²

4. When dividing terms in a bracket, you must divide all the terms in the bracket to the term outside the bracket.

(12 - 8a³) ÷ 4a² = (12 ÷ 4a²) + (- 8a³ ÷ 4a²)

                            = (3a²) + (-2a)

                            = 3a² - 2a

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3