A company produces fruity drinks that contain a percentage of real fruit juice. Drink A contains 20% real fruit juice and Drink B contains 10% real fruit juice. How many liters of real fruit juice would be needed to produce 250 liters of Drink A and 150 liters of Drink B? How many liters of real fruit juice would be needed to produce aa liters of Drink A and bb liters of Drink B?

y = 290 liters Drink B

Step-by-step explanation:

Drink A contains 20% real fruit juice. x liters

and Drink B contains 5% real fruit juice. y liters

y=x+80

20%x +5%y =56.5

20x+5y==5650

-x + y = 80.00

20x + 5 y = 5650.00 2

Eliminate y

multiply (1)by -5

Multiply (2) by 1

5.00 x -5.00 y = -400.00

20.00 x 5.00 y = 5650.00

Add the two equations

25.00 x = 5250.00

/ 25.00

x = 210.00

plug value of x in (1)

-1.00 x + 1.00 y = 80.00

-210.00 + 1.00 y = 80.00

1.00 y = 290.00

y = 290.00

Ans x = 210 liters Drink A

y = 290 liters Drink B

the perimeter is increased by a factor of 2

the discriminant is 64 + 4*1*12 = 112

this is prime.

step-by-step explanation: