Heyy could you help me out?

The mid-point M is (2, 1). M lies in quadrant I, since the x-coordinate is positive and the y-coordinate is positive

Step-by-step explanation:

The coordinates of the midpoint (x, y) of the segment whose endpoints are (x1, y1) and (x2, y2) are x = , y =

∵ M is the midpoint of DE

∵ D = (-1, 4) and E = (5, -2)

∴ x1 = -1 and x2 = 5

∴ y1 = 4 and y2 = -2

→ Use the rule above to find x, y the coordinates of M

∵ x = =

∴ x = 2

∵ y = =

∴ y = 1

∴ The coordinates of the midpoint M are (2, 1)

∵ The x-coordinate is positive and the y-coordinate is positive

∴ M lies in the first quadrant (I)

The mid-point M is (2, 1). M lies in quadrant I, since the x-coordinate is positive and the y-coordinate is positive

the answer is d

step-by-step explanation:

∡ eia and ∡ kij are congruent

step-by-step explanation: