A. (x+2) (x2 +x+2) + 2(x3 + x2)

3x³ + 5x² + 4x + 4

Step-by-step explanation:

Given

(x + 2)(x² + x + 2) + 2(x³ + x²)

To expand the product, each term in the second factor is multiplied by each term in the first factor, that is

x(x² + x + 2) + 2(x² + x + 2) + 2(x³ + x²) ← distribute the parenthesis

= x³ + x² + 2x + 2x² + 2x + 4 + 2x³ + 2x² ← collect like terms

= 3x³ + 5x² + 4x + 4

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.