SYSTEM:
log base root3 of (x-y) = 2

log base 4 of x - log base x of y = 7/6

Step-by-step explanation:

SYSTEM:

log base root3 of (x-y) = 2 1

log base 4 of x - log base x of y =7/6...2

From equation 1:

x-y = (√3)²

x - y = 3 3

From equation 2:

log base 4 of x - log base x of y =7/6

-log base x of 4 - log base x of y = 7/6

log base x of 4^-1 - log base x of y = 7/6

log base x of (1/4) - log base x of y = 7/6

According to law of logarithm

Log base x {1/4 ÷ y} = 7/6

x^7/6 = 1/4y 2

From 1, y = x-3

x^7/6 =1/4(x-3)

x^7/6 = 1/(4x-12)

x^7/6(4x-12) = 1

From

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2