Find the area that is enclosed by the parabola y = x²-3x line y = 2x and line y = -x

39/2

Step-by-step explanation:

First, we find the points of intersection (POI) of the curve and one of the lines:

x²-3x=2x

x²-5x=0

x(x-5)=0

x=0,5

Next, we find the POI of the curve and the second line:

x²-3x=-x

x²-2x=0

x(x-2)=0

x=0,2

To better visualize this, you can go on Desmos.

The area enclosed by all three lines is going to be the area enclosed by the curve and y=-x () subtracted from the area enclosed by the curve and y=2x ().

Since 2x is greater than the curve in the interval [0,5],

=

Solving this, you would get 125/6.

Since -x is greater than the curve in the interval [0,2],

=

Solving this, you would get 4/3.

=125/6-4/3=39/2

Hope this helps!

step-by-step explanation:

consider an orange peel: if you want to try and lay it flat, you have to stretch it, we know exactly how things are being stretched or squashed at any given point. we have many different map projections because each has different patterns of some projections can even preserve certain features of the earth without