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Frequency = 8 Hz ; Period = 0.125 s

Step-by-step explanation:

The amplitude of a wave is simply regarded as the maximum displacement experienced by a vibrating both from its equlibrum position.

The Displacement marked A in th picture is tbe Amplitude of the wave

The wavelength refers to the a complete cycle moved by a wave, that is the distance from a crest to another (maximum upward Displacement) or a trough to another (maximum downward Displacement).

2.)

Given that :

Velocity (V) of wave = 20 m/s

Wavelength (λ) = 2.5 m

The frequency (f) of the wave ;

f = v /λ

f = (20 m/s) ÷ 2.5m

f = 8 Hz

The period T of the wave :

T = 1 /f

T = 1 / 8

T = 0.125 seconds

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this