The difference of the ages of two brothers is 4 years 5 years ago if the product of their ages was 96 find their present ages

OB - Older Brother

YB - Younger Brother

A) OB -YB = 4

B) OB * YB = 96

B) OB = 96 / YB

Multiplying A) by -1

A) -OB + YB = -4 then we add B)

B) OB = 96 / YB

YB = -4 + 96 / YB

Multiplying both sides by YB

YB^2 = -4YB +96 then re-arranging

YB^2 + 4YB -96 = 0 solving by quadratic equation

AS OF 5 years AGO:

Younger Brother's age = 8

Older Brother's age = 12

NOW THEIR AGES ARE:

8 + 4 = 12  YB and

12 + 4 = 16 OB

Step-by-step explanation:

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .