Prove that :-
1+tan 4 A tan2A = seca A

seca A

Step-by-step explanation:

Use z=a+bi=|z|(cos(θ)+isin(θ))z=a+bi=|z|(cos(θ)+isin(θ)) to find the trigonometric form.

√tan(4A)tan2(2A)+1(cos(arctan(tan(4A)tan(2A)1))+isin(arctan(tan(4A)tan(2A)1)))tan(4A)tan2(2A)+1(cos(arctan(tan(4A)tan(2A)1))+isin(arctan(tan(4A)tan(2A)1)))

the monthly balance will be $75,000

answer: it actually depends on which is the independent variable and which is the dependent variable. let us say we're looking at a linear equation. y=2x+3. we theoretically could switch the equation to be x=(y-3)/2 and it would be the same line. so either a causes b or it can be that b causes a. so technically the answer is false

step-by-step explanation: