Please help! 20 points + brainliest (***NOTICE: Bots/trolls seeking points will be reported.***)

Solve these two equations:

For the first one we divide every element by sqrt3

we get

q+2/sqrt3 =sqrt5/sqrt3

q=(sqrt5-2)/sqrt3

q=sqrt3*sqrt5-2*sqrt3/3

q=sqrt15-2sqrt3/3

which is the third option

For the second one

sqrt(2y-5) +4=8

first we move the 4 to the right

sqrt(2y-5)=4

we remove the square root by bringing to the power of two

2y-5=16

2y=21

y=21/2

y=10 1/2

third option

answer: 2530

hope this

no

step-by-step explanation: