Write the simplest polynomial function for each set of zeros Zeros = 2,-2, 4, 1

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  p(x) = x^4 -5x^3 +20x -16

Step-by-step explanation:

If 'a' is a zero of the polynomial, then (x -a) will be a factor. For the given zeros, the simplest polynomial will be the product of the corresponding factors:

  p(x) = (x -2)(x +2)(x -4)(x -1) . . . . . . note that x -(-2) = x +2 (factored form)

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Multiplying these out gives the result in standard form.

The product of the first two factors is a "special product" recognizable as the difference of two squares.

  (x -2)(x +2) = x^2 -2^2 = x^2 -4

The product of the last two factors can be found in the usual way. The distributive property applies.

  (x -4)(x -1) = x(x -1) -4(x -1)

  = x^2 -x -4x +4 = x^2 -5x +4

Then the full polynomial is the product of these partial products:

  p(x) = (x^2 -4)(x^2 -5x +4)

  = x^2(x^2 -5x +4) -4(x^2 -5x +4)

  = x^4 -5x^3 +4x^2 -4x^2 +20x -16

  p(x) = x^4 -5x^3 +20x -16 . . . . . . . . standard form

a) one student is chosen from classroom a, then a student is chosen from classroom b.  

step-by-step explanation:

independent events are ones in which the probability of one event does not affect the probability of the second event.

one student is chosen from classroom a; this does not affect the chances of choosing a student from classroom b.   this makes these independent events.

when one card is chosen from a standard deck and then set aside before a second card is chosen, the probability of the second card being chosen changes.   this makes them dependent events.

when one student is chosen from classroom a and then a second student is chosen from classroom a, the probability of choosing the second student changes.   this makes them dependent events.

when a letter is chosen from the alphabet and then a second letter is chosen, the probability of choosing the second letter changes.   this makes them dependent events.

you would have to sell 24 bracelets.

step-by-step explanation:

84/3.5 = 24