Suppose that 2% of produced computers by a company have defects, and defects occur independently of each other. a) Find the probability of exactly 2 defective computers in a shipment of 100 computers. b) The probability that a computer support specialist needs to test at least N computers in order to find one defective computer is 0.6676. Find N.

a)  P(exactly two defectives) = 0.2734

b) N 55

Step-by-step explanation:

From the given information:

P(exactly two defectives) = P(X =2) =

= 0.2734

Thus, P(exactly two defectives) = 0.2734

b)

To find:

P(X ≥ 1 )

let X be the random variable that obeys a binomial distribution, X represents the number of defectives,

∴

N log (0.98) = log (0.3324)

N = 54.51824841

N 55

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.