One angle of an isosceles triangle measures 56°. Which other angles could be in that isosceles triangle? .

x+x+56=180

2x=180-56

x=124/2

x=62

Step-by-step explanation:

one angle is already given which is 56. Now it is an isosceles triangle so the rest two unknown angles might be same so i named them as 'x'. So holding them as x i used the same formula to find the angles.

68 or 62 degrees

Step-by-step explanation:

If the 56 degree angle is one of the base angles of the triangle, you can multiply it by two (because base angles of an isosceles triangle

are congruent), and then subtract 180 (because you must subtract the sum of two angles from 180 to get the measure of the third angle).

If the 56 degree is not a base angle, then you can use this equation to get the measurement of each base angle:

(180-56)÷2=measure of each base angle

180=sum of angle measures in a triangle

56=measure of third angle

With 180-56, you get the sum of the base angles, so you must divide by two. (Base angles of an isosceles triangle are congruent)

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.