WILL GIVE BRAINLIST AND PLS INCLUDE HOW YOU SOLVED IT! The relationship between altitude and the boiling point of a liquid is linear. At an altitude of 8200 it, the liquid boils at
195.42°F. At an altitude of 4300 ft, the liquid boils at 202.83F. Write an equation giving the boiling point b of the liquid,
in degrees Fahrenheit, in terms of altitude a, in feet. What is the boiling point of the liquid at 2500 it?
Write an equation

b = -0.0019a + 211

at a=2500, b=215.75

Step-by-step explanation:

The points we get from the problem are

(8200 , 195.42)

(4300, 202.83)

where a= altitude and b=boiling point in degrees F

to find slope by b2-b1 / a2-a1

(202.83 - 195.42) / (4300-8200)

= 7.41 / -3900

= -0.0019

we have b = -0.0019a + intercept

substitute in one point to figure out intercept

195.42 = -0.0019(8200) + intercept

195.42 = -15.58 + intercept

add 15.58 to both sides

195.42 + 15.58 = -15.58 + 15.58 + intercept

intercept = 211

b = -0.0019a + 211

At an altitude of 2500ft (a=2500) find b.

b = -0.0019(2500) + 211

b = 4.75 + 211 = 215.75

b = 215.75 degrees F

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-10i^2-4i

step-by-step explanation:

evaluate for p=2,q=5i

(2−4)(2+5i)i

(2−4)(2+5i)i

=−10i2−4i

b. y = 4x - 2

step-by-step explanation:

to find a parallel equation to an equation, make sure both equations have the same slope but different y-intercepts.

y = 4x + 1

4 = slope

1 = y-intercept

y = 4x - 2

4 = slope

-2 = y-intercept

they both have the same slope but different y-intercepts, so, b. is the correct answer.

and to check your work, you can graph both equations. : )