In parallelogram BCDE if CE= 32 find GF
Please help I’ll give brainliest

CF = 16

Step-by-step explanation:

One if the properties of a parallelogram is that the diagonals of a parallelogram bisect each other. This implies that:

CF = ½ of CE

Since CE is given as 32, therefore:

CF = ½ of 32

CF = 16

lockers 1, 4, 9, 16, 25, 40, and 49 are open

i ran through it by the other answer is wrong

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)