Pls hurry I need the answer

Work Shown:

Apply the law of cosines

a^2 = b^2 + c^2 - 2*b*c*cos(A)

10^2 = 13^2 + 11^2 - 2*13*11*cos(A)

100 = 290 - 286*cos(A)

100-290 = -286*cos(A)

-190 = -286*cos(A)

190 = 286*cos(A)

286*cos(A) = 190

cos(A) = 190/286

A = arccos(190/286)

A = 48.368620460647

A = 48

Make sure your calculator is in degree mode.

all it means is function 3

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: