In a study investigating a link between walking and improved health, researchers reported that adults walked an average of minutes in the past month for the purpose of health or recreation. Specify the null and alternative hypotheses for testing whether the true average number of minutes in the past month that adults walked for the purpose of health or recreation is than minutes.

Complete question is;

In a study investigating a link between walking and improved health, researchers reported that adults walked an average of 873 minutes in the past month for the purpose of health or recreation.

Specify the null and alternative hypotheses for testing whether the true average number of minutes in the past month that adults walked for the purpose of health or recreation is lower than 873 minutes

Null Hypothesis: H0: μ = 873

Alternative hypothesis: Ha: μ < 873

Step-by-step explanation:

From the study, the claim is that the true average number of minutes gotten from the population average in the past month that the adults had walked for the purpose of health or recreation is lower than the average of 873 minutes.

Now, the population study says it's equal to 873 minutes.

Thus, the hypotheses can be written as;

Null Hypothesis: H0: μ = 873

Alternative hypothesis: Ha: μ < 873

283 square feet

step-by-step explanation:

good luck

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.