Monitors manufactured by TSI Electronics have life spans that have a normal distribution with a standard deviation of 15001500 hours and a mean life span of 16,00016,000 hours. If a monitor is selected at random, find the probability that the life span of the monitor will be more than 18,09918,099 hours.

0.0809

Step-by-step explanation:

Given that :

Mean(m) = 16000

Standard deviation (s) = 1500

Probability that the life span of the monitor will be more than 18,099

P(x > 18099)

Using the Zscore formula :

Zscore =(x - m) / s

Zscore = (18099 - 16000) / 1500

Zscore = 2099 / 1500

Zscore = 1.399

P(Z > 1.399)

Using the Z probability calculator :

P(Z > 1.399) = 0.080906

= 0.0809

i would say b) is your answer

sorry if im wrong

step-by-step explanation:

.95

step-by-step explanation: