For geometry:(

please help, will give brainist

The equation of the line segment to the line segment with end point (4, 4) and (-8, 8) is y = x/3 - 4

Step-by-step explanation:

The coordinates of the given points are;

(4, 4) and (-8, 8)

Therefore;

Where;

y₁ = 4, y₂ = -8, x₁ = 4, x₂ = 8

Therefore, the slope, m of the given line segment = (-8 - 4)/(8 - 4) = -3

The slope of the perpendicular line segment = -1/m = -1/(-3) = 1/3

The mid point of the line segment with endpoint (4, 4) and (-8, 8) is given as follows;

Therefore, the midpoint  = ((4 + 8)/2, (4 + (-8))/2) = (6, -2)

The equation of the perpendicular line segment in point and slope form is given as follows;

y - (-2) = 1/3 × (x - 6)

Which gives;

y + 2 = x/3 - 6/3 = x/3 - 2

y = x/3 - 2 - 2 = x/3 - 4

The equation of the line segment to the line segment with end point (4, 4) and (-8, 8) is y = x/3 - 4

the value of x is 9 ⇒ answer b

step-by-step explanation:

* we can solve this problem using cosine and sine rule

- in δ abc

∵ ab = 36 , bc = 28 , ac = 16

- lets find the measure of angle b using the cosine rule

∵ cos b = [ab² + bc² - ac²]/2(ab)(bc)

∴ cos b = [36² + 28² - 16²]/2(36)(28)

∴ cos b = 19/21

∴ m∠b = cos^-1(19/21) ≅ 25°

- lets find the measure of angle a using the sine rule

∵ sina/bc = sinb/ac = sinc/ab

∴ sina/28 = sin25°/16 ⇒ by using cross multiplication

∴ sina = 28 × sin25°/16

∴ sina = 0.7396

∴ m∠a = sin^-1(0.7396) ≅ 48°

- from the figure m∠abd = m∠dbc

∵ m∠abc = 25°

∴ m∠abd = 25°/2 = 12.5°

- in δabd

∵ m∠a = 48° , m∠abd = 12.5°

∵ the sum of the measures of the interior angles of any δ is 180°

∴ m∠adb = 180° - (48° + 12.5°) = 119.5°

∵ ab = 36

∵ ad = x

- use the sine rule to find x

∵ sin∠adb/ab = sin∠abd/x

∴ sin119.5°/36 = sin12.5°/x ⇒ by using cross multiplication

∴ x = 36 × sin12.5°/sin119.5° = 8.95 ≅ 9

* the value of x is 9

time is equal to distance over rate so

t = d/r

need a little bit more information for the second question.