A consultant advises the owners of a phone company that their profit p each month car-be modeled by
p(x) = -50x2 + 3500x - 2500
The variable x is the average cost that a customer is charged. What
range of costs will bring in a profit of at least $40,000?

$15.63 ≤ x ≤ $54.365

Step-by-step explanation:

Profit of the phone company is modeled by the equation,

p(x) = -50x² + 3500x - 2500

For the profit of at least $40000,

-50x² + 3500x - 2500 ≥ 40000

-50x² + 3500x ≥ 40000 + 2500

-50x² + 3500x ≥ 42500

-x² + 70x ≥ 850

x² - 70x + 850 ≤ 0

By quadratic formula,

x - intercept of the inequality will be,

x =

x =

x = 15.635, 54.365

Therefore, $15.635 ≤ x ≤ $54.365 will be the range of cost for which profit will be at least $40000.

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3